f(x)= the square root of x plus 3
x + 3 is under the radical.
thanks
ooh yes, I remember that now.
now.... how do I find the range?
here's the dilemma... when you find the inverse of that function, the domain of that should be the range of the original function, so y= x^2 - 3
the range for that would be all real numbers, but when graphed, it looks like an asymptote approaching 0. how would that work?
thanks.