I can't figure this out:
0 = x^3 - 4x
What is x?
I could guess for x, but how do I solve this arithmetically?
Thank you,
Patrick
$\displaystyle 0 = x^3-4x$
Factor an x,
$\displaystyle 0 = (x)\cdot(x^2-4)$
Now, you can see that if one of these factors are zero, then the equation is satisfied.
We're looking for cases where either $\displaystyle x=0$ or $\displaystyle x^2-4=0$.
I think you can solve from here.