# simple algebra

Printable View

• August 17th 2008, 01:58 PM
DonPatricio
simple algebra
I can't figure this out:

0 = x^3 - 4x
What is x?

I could guess for x, but how do I solve this arithmetically?
Thank you,
Patrick
• August 17th 2008, 02:08 PM
skeeter
try factoring the expression on the right side of the equation and using the zero product property to solve for x.
• August 17th 2008, 02:08 PM
wingless
$0 = x^3-4x$

Factor an x,
$0 = (x)\cdot(x^2-4)$

Now, you can see that if one of these factors are zero, then the equation is satisfied.

We're looking for cases where either $x=0$ or $x^2-4=0$.

I think you can solve from here.
• August 18th 2008, 08:25 PM
DonPatricio
Thank you guys. That really helped a lot ..