# Math Help - Help me please

1. Originally Posted by Chester
I am a little confused (not that that’s hard to do at this point.) But the problem is

$
\frac{\sqrt3}{\sqrt{6-1}}-\frac{\sqrt3}{\sqrt{6+1}}
$

Not

$
\frac{\sqrt3}{\sqrt{6-1}}=\frac{\sqrt3}{\sqrt{6+1}}$

Do I solve this the same way?
No you definitely do not. let me explain why I wrote $
\frac{\sqrt3}{\sqrt{6-1}}=\frac{\sqrt3}{\sqrt{6-1}}$

everyone knows that $x-x=0$

now look at your paper and you realize that you wrote [tex]
$\frac{\sqrt3}{\sqrt{6-1}}-\frac{\sqrt3}{\sqrt{6-1}}$
so I was just pointing out the obvious by saying they were zero.

but now you write $\frac{\sqrt3}{\sqrt{6-1}}-\frac{\sqrt3}{\sqrt{6+1}}$ which is COMPLETELY different, in fact right now I'm drawing a blank on this problem (I feel like the answers easy to get, but I just can't think of it)

2. ## Problem

The problem says to "simplify"

I am at a loss also. Buti will keep looking.

Thanks again,
Chester

3. Originally Posted by Chester
The problem says to "simplify"

I am at a loss also. Buti will keep looking.

Thanks again,
Chester
My only thought is that you might want to rationalize the denominator in each term. This has the result that both terms will have the same denominator and then can be added.

-Dan

4. ## Thanks Dan

I will see what i come up with

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