No you definitely do not. let me explain why I wrote $\displaystyleOriginally Posted byChester

\frac{\sqrt3}{\sqrt{6-1}}=\frac{\sqrt3}{\sqrt{6-1}} $

everyone knows that $\displaystyle x-x=0$

now look at your paper and you realize that you wrote [tex]

$\displaystyle \frac{\sqrt3}{\sqrt{6-1}}-\frac{\sqrt3}{\sqrt{6-1}} $

so I was just pointing out the obvious by saying they were zero.

but now you write $\displaystyle \frac{\sqrt3}{\sqrt{6-1}}-\frac{\sqrt3}{\sqrt{6+1}} $ which is COMPLETELY different, in fact right now I'm drawing a blank on this problem (I feel like the answers easy to get, but I just can't think of it)