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Math Help - this might be hard.

  1. #1
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    Red face this might be hard.

    there are eight guys on the team. if the average weight of the team was 250.5 pounds and the heaviest guy weighed 264 pounds, what was the average weight of the other seven guys? Express your answer as a decimal to the nearest tenths. please answer . oh and also please tell me how you got the answer cause i need to learn how to do it.
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  2. #2
    MHF Contributor
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    Just think it through. Remember TOTAL weight is important.

    \frac{(8*250.5)\;-\;264}{7}
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  3. #3
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    Hello, tika!

    You can think your way through this problem . . .


    There are eight guys on the team.
    If the average weight of the team was 250.5 pounds
    and the heaviest guy weighed 264 pounds,
    what was the average weight of the other seven guys?
    Express your answer as a decimal to the nearest tenth.
    Call the men's weights: .  A,B,C,D,E,F,G,H

    Their average weight is 250.5 pounds.
    We would add the eight weights and divide by 8, right?

    . . So we have: . \frac{A+B+C+D+E+F+G+H}{8} \:=\:250.5

    . . That is: . A + B+C+D+E+F+G+H \:=\:2004\;\;{\color{blue}[1]}

    The entire team weighs 2004 pounds.


    The heaviest (say, H) weighs 264 pounds.

    . . Substitute into [1]: . A+B+C+D+E+F+G+264 \:=\:2004

    . . So we have: . A+B+C+D+E+F+G \:=\:1740

    Hence, the other seven members weigh a total of 1740 pounds.


    Therefore, their average weight is: . \frac{1740}{7} \;=\;248.5714... \;\approx\;248.6 pounds.

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