# Thread: this might be hard.

1. ## this might be hard.

there are eight guys on the team. if the average weight of the team was 250.5 pounds and the heaviest guy weighed 264 pounds, what was the average weight of the other seven guys? Express your answer as a decimal to the nearest tenths. please answer . oh and also please tell me how you got the answer cause i need to learn how to do it.

2. Just think it through. Remember TOTAL weight is important.

$\frac{(8*250.5)\;-\;264}{7}$

3. Hello, tika!

You can think your way through this problem . . .

There are eight guys on the team.
If the average weight of the team was 250.5 pounds
and the heaviest guy weighed 264 pounds,
what was the average weight of the other seven guys?
Call the men's weights: . $A,B,C,D,E,F,G,H$

Their average weight is 250.5 pounds.
We would add the eight weights and divide by 8, right?

. . So we have: . $\frac{A+B+C+D+E+F+G+H}{8} \:=\:250.5$

. . That is: . $A + B+C+D+E+F+G+H \:=\:2004\;\;{\color{blue}[1]}$

The entire team weighs 2004 pounds.

The heaviest (say, $H$) weighs 264 pounds.

. . Substitute into [1]: . $A+B+C+D+E+F+G+264 \:=\:2004$

. . So we have: . $A+B+C+D+E+F+G \:=\:1740$

Hence, the other seven members weigh a total of 1740 pounds.

Therefore, their average weight is: . $\frac{1740}{7} \;=\;248.5714... \;\approx\;248.6$ pounds.