Thread: I am stuck again!

mathhelpforum users, I need your help!

While doing some homework, I got stuck on a few problems.

Find the simplest equivalent expression for each of the following:


4xsquared - 64/12xsquared - 60x + 48

2xsquared - 128/4xsquared - 36x + 32

Please show how you got the answer, so that I can learn from difficulties.
Any help will be appreciated!

Given:

Multiply by 12 to get rid of the fraction:

Combine the :

You can pull -16 as common factor:

Now do the same for question number 2

Do you also need to factor?

Hello, Joker37!


Please use parentheses when writing fractions . . .

(4xsquared - 64) / (12xsquared - 60x + 48)

We have: .


Factor . . .

Numerator: .

Denominator: .


The fraction becomes: .


Reduce: .

(2xsquared - 128) / (4xsquared - 36x + 32)

The same routine . . .

(2xsquared - 128)/(4xsquared - 36x + 32)

2(xsquared - 64)
2(xsquared - 8squared)
2(x - 8)(x + 8)

4xsquared - 36x + 32
4(xsquared - 9x +8)
4(x - 1)(x - 8)

So, (2(x - 8)(x + 8))/(4x(x - 1)(x - 8))
= ((x + 8))/(2(x - 1))

Is this right?

EDIT: Soz, I forgot the parentheses

Originally Posted by Joker37

(2xsquared - 128)/(4xsquared - 36x + 32)

2(xsquared - 64)
2(xsquared - 8squared)
2(x - 8)(x + 8)

4xsquared - 36x + 32
4(xsquared - 9x +8)
4(x - 1)(x - 8)

So, (2(x - 8)(x + 8))/(4x(x - 1)(x - 8))
= ((x + 8))/(2(x - 1))

Is this right?

EDIT: Soz, I forgot the parentheses

You are correct: