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Math Help - [SOLVED] division of an algebric expression

  1. #1
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    Question [SOLVED] division of an algebric expression

    Please check if this is right:

     \frac {2^{-3}a^ \frac {2}{3} b^4}{2^{-2}a^ \frac {1}{6} b^4}

    1^{-3-(-2)} a^{\frac {2}{3}-\frac {1}{6}} b^{4-4}

    1^{-1} a^{\frac {4}{6}-\frac {1}{6}}

    1 a^{\frac {3}{6}}

    a^{\frac {3}{6}}

    a^{\frac {1}{2}}

    \sqrt{a}

    The exposants can't be fractions for the answer to be right...

    (wow this was tough code to write!!!)

    I'm really starting to hate math! sorry
    Last edited by Neenoon; August 16th 2008 at 05:47 AM.
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  2. #2
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    Hello, Neenoon!

    One correction . . .

     \frac {2^{\text{-}3}\,a^{\frac{2}{3}}\,b^4}{2^{-2}\,a^{\frac{1}{6}}\,b^4} \;\;=\;\;{\color{red}2}^{\text{-}3-(\text{-}2)}\,a^{\frac{2}{3}-\frac {1}{6}}\,b^{4-4} \;\;=\;\;2^{-1} a^{\frac {4}{6}-\frac {1}{6}}b^0 \;\;=\;\;\frac{1}{2}\,a^{\frac{1}{2}} \;\;=\;\;\frac{1}{2}\sqrt{a}

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  3. #3
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    Thank you. I don't understand though, how come the 2 devided by 2, still stays 2?
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by Neenoon View Post
    Thank you. I don't understand though, how come the 2 devided by 2, still stays 2?
    It's NOT 2 divided by 2. Don't ignore the exponent in this case. Here's the rule:

    \frac{x^a}{x^b}=x^{a-b}

    You see. The x (base) stayed the same. We only subtracted the exponents.
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  5. #5
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    Quote Originally Posted by masters View Post
    It's NOT 2 divided by 2. Don't ignore the exponent in this case. Here's the rule:

    \frac{x^a}{x^b}=x^{a-b}

    You see. The x (base) stayed the same. We only subtracted the exponents.
    Really!?!? Hummmm.... I better check all my homework for such a case!

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