I am not sure if i entered this correctly

$\displaystyle

\frac {{ab+b^2}{4ab^5}}{{a+b}{6a^2b^4}}

$

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- Jul 31st 2006, 07:08 PMChesterComplex fraction
I am not sure if i entered this correctly

$\displaystyle

\frac {{ab+b^2}{4ab^5}}{{a+b}{6a^2b^4}}

$ - Jul 31st 2006, 07:10 PMQuickQuote:

Originally Posted by**Chester**

$\displaystyle

\frac{\frac{ab+b^2}{4ab^5}}{\frac{a+b}{6a^2b^4}}

$

but that seems silly, with the bracket you left out your expression is:

$\displaystyle

\frac {{ab+b^2}{4ab^5}}{{a+b}{6a^2b^4}}

$

but I don't understand... - Jul 31st 2006, 07:13 PMChesterAnother try
$\displaystyle

\frac{ \frac{ab+b^2}{4ab^5} }{ \frac{a+b}{6a^2b^4}}

$ - Jul 31st 2006, 07:14 PMQuickQuote:

Originally Posted by**Chester**

$\displaystyle \frac{ab+b^2}{4ab^5} \div \frac{a+b}{6a^2b^4}$ - Jul 31st 2006, 07:16 PMChesterClarification
Sorry,

I was trying to get the code to work. That is what i am saying. I have to simplify and reduce.

Thanks - Jul 31st 2006, 07:27 PMChesterAnother try
Rational expressions

I have to simplify and reduce the following

$\displaystyle

\frac{ \frac{ab+b^2}{4ab^5} }{ \frac{a+b}{6a^2b^4}}

$

Chester - Jul 31st 2006, 07:31 PMQuickQuote:

Originally Posted by**Chester**

Quote:

$\displaystyle

\frac{ab+b^2}{4ab^5} \div \frac{a+b}{6a^2b^4}

$

multiply: $\displaystyle \frac{(ab+b^2)(6a^2b^4)}{(4ab^5)(a+b)}$

seperate: $\displaystyle \frac{ab+b^2}{a+b} \times \frac{6a^2b^4}{4ab^5}$

divide: $\displaystyle \frac{ab+b^2}{a+b} \times \frac{6a}{4b}$

multiply: $\displaystyle \frac{6a(ab+b^2)}{4b(a+b)}$

multiply: $\displaystyle \frac{6a^2b+6b^2a}{4ab+4b^2}$

split: $\displaystyle \frac{6a^2b}{4ab+4b^2}+\frac{6b^2a}{4ab+4b^2}$

simplify: $\displaystyle \frac{6a^2b}{4b(b+a)}+\frac{6b^2a}{4b(b+a)}$

simplify: $\displaystyle \frac{3a^2}{2(b+a)}+\frac{3ab}{2(b+a)}$

add: $\displaystyle \frac{3a^2+3ab}{2(b+a)}$

combine: $\displaystyle \frac{3a(a+b)}{2(b+a)}$

seperate: $\displaystyle \frac{3a}{2}\times\frac{a+b}{b+a}$

simplify: $\displaystyle \frac{3a}{2}\times1$

simplify: $\displaystyle \frac{3a}{2}$

I might have done more work than necessary, but I got the job done... - Jul 31st 2006, 07:35 PMQuickshorter "quicker" workQuote:

Originally Posted by**Quick**

simplify: $\displaystyle b \times \frac{3a}{2b}$

multiply: $\displaystyle \frac{3ab}{2b}$

simplify: $\displaystyle \frac{3a}{2}$ - Jul 31st 2006, 07:57 PMChesterLcd
I would like to solve this by finding the LCD and simplifying.

I think the LCD will be 12a^2b^5

Is that the corect start? - Aug 1st 2006, 03:56 AMtopsquarkQuote:

Originally Posted by**Chester**

-Dan - Aug 1st 2006, 07:48 AMQuickQuote:

Originally Posted by**Chester**

- Aug 1st 2006, 08:00 AMtopsquarkQuote:

Originally Posted by**Quick**

-Dan