I'm trying to solve the equality $\displaystyle \frac{{2x - 1}}{{x + 1}} < 3 \$
$\displaystyle
\begin{array}{l}
\frac{{2x - 1}}{{x + 1}} < 3 \\
2x - 1 < 3(x + 1) \\
2x - 1 < 3x + 3 \\
- 4 < x \\
\end{array}
$
I can't work out how to get the second solution of x > -1