Complex fractions

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July 31st 2006, 04:20 PM
Chester

Complex fractions

Please see attached

Thanks
Chester
July 31st 2006, 04:28 PM
topsquark

Your method is correct, but your denominator is slightly incorrect.

$\frac{ \frac{1}{3} + \frac{1}{y} }{ \frac{y}{3} - \frac{3}{y} }$ $\times \frac{3y}{3y}$

$= \frac{ \frac{1}{3}(3y)+ \frac{1}{y}(3y) }{ \frac{y}{3}(3y) - \frac{3}{y}(3y) }$

$= \frac{ y+ 3 }{ y^2 - 9 }$

$= \frac{y+3}{(y+3)(y-3)} = \frac{1}{y-3}$ , $y \neq 3, \, -3, \, 0$

-Dan
July 31st 2006, 04:39 PM
Chester

Thanks

I just need to simplify and reduce to lowest term.

would this be correct?

y+3
----------
(y+3)(y-3)

Chester. How to you post your response?
July 31st 2006, 04:52 PM
topsquark

Quote:

Originally Posted by Chester

I just need to simplify and reduce to lowest term.

would this be correct?

y+3
----------
(y+3)(y-3)

Chester. How to you post your response?

Once you cancel the common y+3, yes.

I'm not sure what you mean by "post your response?"

-Dan
July 31st 2006, 05:31 PM
Chester

How you post your response

Thanks. I would like to find out how you make your posts look like they are done in equation editor. Are there any instructions on the site for doing this?

Thanks again for your time

Chester
July 31st 2006, 05:40 PM
topsquark

Quote:

Originally Posted by Chester

Thanks. I would like to find out how you make your posts look like they are done in equation editor. Are there any instructions on the site for doing this?

Thanks again for your time

Chester

(Sigh) I can't find the link. Somewhere in here is a quick set of instructions. Briefly, if you want to see how the text is coded, left-click on the expression and a box will come up.

The basics are that all code for LaTeX on this forum is in between the two sets of boxes " [ math ] " and " [ /math ] ." (Without the spaces and quotes!) A decent reference for basic forms can be found here: http://meta.wikimedia.org/wiki/Help:Formula

So far, everything I've found on this page works in this forum.

Common examples:
$x^2$

$x_1$

$x_1^3$

$\sqrt{ x^{3/2} }$

$\frac{x-1}{x^2+2x}$

You get used to it after a while. :)

-Dan
July 31st 2006, 06:54 PM
Quick

Quote:

Originally Posted by topsquark

(Sigh) I can't find the link.

-Dan

They really should post the LaTex Tutorial as a sticky in one of the forums.
July 31st 2006, 07:03 PM
ThePerfectHacker

Quote:

Originally Posted by Quick

They really should post the LaTex Tutorial as a sticky in one of the forums.

Not a bad idea.