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Math Help - Divisions With "big" Numbers

  1. #1
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    Divisions With "big" Numbers

    Ok... They're not big numbers.

    --

    Is there a proper method to do these divisions without a calculator?

    1104/48 = 23

    To do that sum, I would multiply 48 by 10 to get 480 and then double it to get 960. I would then keep subtracting 48 from 144 (1104 - 960) until I get 0. Is there a proper way of doing this?

    Thanks.
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  2. #2
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    Quote Originally Posted by r_maths View Post
    Ok... They're not big numbers.

    --

    Is there a proper method to do these divisions without a calculator?

    1104/48 = 23

    To do that sum, I would multiply 48 by 10 to get 480 and then double it to get 960. I would then keep subtracting 48 from 144 (1104 - 960) until I get 0. Is there a proper way of doing this?

    Thanks.
    Try here: Long Division

    for an excellent explanation.
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  3. #3
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    Quote Originally Posted by r_maths View Post
    Ok... They're not big numbers.

    --

    Is there a proper method to do these divisions without a calculator?

    1104/48 = 23

    To do that sum, I would multiply 48 by 10 to get 480 and then double it to get 960. I would then keep subtracting 48 from 144 (1104 - 960) until I get 0. Is there a proper way of doing this?

    Thanks.
    hi
    To divide 1104/48
    First u have to see the first three digits out of four digits ok
    here the number is 1104 right
    in that take 110
    then u have to recite the multiple of 48 ok
    48*1=48,48*2=96,48*3=144 -Here u have to compare the answer with the multiples of 48
    110 is given in the problem
    less than 110 is 96 which is the multiple of 48*2
    The remainder is 14 there the fourth digit given in the problem is 4 - so 144
    then 48*3=144 we know
    Hence the answer u got 1104/48 =23
    I think that u may understood now
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  4. #4
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    Quote Originally Posted by r_maths View Post
    Ok... They're not big numbers.

    --

    Is there a proper method to do these divisions without a calculator?

    1104/48 = 23

    To do that sum, I would multiply 48 by 10 to get 480 and then double it to get 960. I would then keep subtracting 48 from 144 (1104 - 960) until I get 0. Is there a proper way of doing this?

    Thanks.
    One way is by cancellation in reducing the original fraction into its simplest form.

    1104 / 48.
    1104 and 48 are divisible by 2. So cancell the 2 from both,
    = 552 / 24

    552 and 24 are again each divisible by 2. Cancell again 2 from each,
    = 276 / 12

    Again, cancel 2 from 276 and 12,
    = 138 / 6

    Again,
    = 69 / 3

    Finally,
    = 23.
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