a and b are negative integers, if $\displaystyle a>b$ $\displaystyle a.b=5(a-b)$ $\displaystyle b=?$ a)-20 b)-12 c)-8 d)4 e)21
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Originally Posted by OPETH a and b are negative integers, if $\displaystyle a>b$ $\displaystyle a.b=5(a-b)$ $\displaystyle b=?$ a)-20 b)-12 c)-8 d)4 e)21 please don't ask us every problem you have for homework, try doing them yourself and if you're really really stuck on one, then post it.
Originally Posted by Quick please don't ask us every problem you have for homework, try doing them yourself and if you're really really stuck on one, then post it. Homework? Those questions are not my homework. I wanted to solve those. I found " 4 " the result.
Originally Posted by OPETH a and b are negative integers, if $\displaystyle a>b$ $\displaystyle a.b=5(a-b)$ $\displaystyle b=?$... Originally Posted by OPETH ... I found " 4 " the result. Ähemm! Since $\displaystyle b = \frac{5a}{a+5} = 5-\frac{25}{a+5}$ and both numbers should be negative I've got a = -4 and b = -20. Obviously the condition a > b is satisfied.
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