question5

• Aug 12th 2008, 07:08 AM
OPETH
question5
a and b are negative integers,

if $\displaystyle a>b$

$\displaystyle a.b=5(a-b)$

$\displaystyle b=?$

a)-20 b)-12 c)-8 d)4 e)21
• Aug 12th 2008, 07:10 AM
Quick
Quote:

Originally Posted by OPETH
a and b are negative integers,

if $\displaystyle a>b$

$\displaystyle a.b=5(a-b)$

$\displaystyle b=?$

a)-20 b)-12 c)-8 d)4 e)21

please don't ask us every problem you have for homework, try doing them yourself and if you're really really stuck on one, then post it.
• Aug 12th 2008, 07:26 AM
OPETH
Quote:

Originally Posted by Quick
please don't ask us every problem you have for homework, try doing them yourself and if you're really really stuck on one, then post it.

Homework? Those questions are not my homework.

I wanted to solve those.

I found " 4 " the result.
• Aug 12th 2008, 09:44 AM
earboth
Quote:

Originally Posted by OPETH
a and b are negative integers,

if $\displaystyle a>b$

$\displaystyle a.b=5(a-b)$

$\displaystyle b=?$...

Quote:

Originally Posted by OPETH
...

I found " 4 " the result.

Ähemm!

Since $\displaystyle b = \frac{5a}{a+5} = 5-\frac{25}{a+5}$
and both numbers should be negative I've got a = -4 and b = -20. Obviously the condition a > b is satisfied.