Reduce each algebraic fraction.

$\displaystyle \frac{4-2u}

{u^3-8}$

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- Aug 11th 2008, 11:50 AMcomet2000Operations on Algebraic Fractions
Reduce each algebraic fraction.

$\displaystyle \frac{4-2u}

{u^3-8}$ - Aug 11th 2008, 11:59 AMQuick
so is it $\displaystyle \frac{4-2u}{u^3-8}$?

I'll assume it is.

So let's rewrite things: $\displaystyle \frac{2(2-u)}{(u-2)(u^2+2u+2)}$

Let's move that negative: $\displaystyle \frac{2(2-u)}{-1(2-u)(u^2+2u+2)}$

Now we can cancel out the 2-u to get: $\displaystyle \frac{2}{-1(u^2+2u+2)}$

So therefore: $\displaystyle \frac{4-2u}{u^3-8}=\frac{-2}{u^2+2u+2}$