$\displaystyle a.b+a+b=34$

$\displaystyle a+b=?$

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- Aug 9th 2008, 02:13 PMOPETHHow I can solve that question?
$\displaystyle a.b+a+b=34$

$\displaystyle a+b=?$ - Aug 9th 2008, 02:16 PMDubulus
do a and b have to be integers?

- Aug 9th 2008, 02:23 PMOPETH
- Aug 9th 2008, 02:54 PMPlato
$\displaystyle a + b = 10$????????

- Aug 9th 2008, 03:10 PMDubulus
a = 17

b = 0

17.0 + 17 + 0 = 34

why is that the only answer?

b needs to be 0 because otherwise the sum would have a decimal in it. since 34 is an integer, we cannot have that. - Aug 9th 2008, 03:38 PMPlato
- Aug 9th 2008, 03:46 PMOPETH
- Aug 9th 2008, 04:05 PMPlato
No, I cannot explain how I solved the problem!

First assume that we are dealing with natural numbers (positive).

I just know a great deal about how numbers work.

It does not take much to see that the integers must be less that ten.

It was simple to try various combinations. - Aug 9th 2008, 04:23 PMDubulus
my bad i thought the problem was saying a.b as in a decimal, ex 4.6 not 4*6

- Aug 11th 2008, 04:17 AMmr fantastic
- Aug 11th 2008, 06:35 AMDubulus
17.0 = 17 just like 14.5 = 14.50...

if the . has another notation im not familiar with, my bad. - Oct 19th 2008, 04:50 AMHallsofIvy