for the problem y = abs( x+2 ) - 3

i understand the vertex is (-2, -3)

is there also a domain and range?

i don't there is....

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- Aug 8th 2008, 12:35 PMzooanimal98finding domain and range
for the problem y = abs( x+2 ) - 3

i understand the vertex is (-2, -3)

is there also a domain and range?

i don't there is.... - Aug 8th 2008, 02:04 PMSigyn3
Domain is $\displaystyle (-\infty,\infty)$, range is $\displaystyle [-3,\infty)$.

- Aug 8th 2008, 06:56 PMTKHunny
What an odd question. If it exists, there is a Domain and a range.

Quote:

i don't [think] there is....

Domain - What can you put in? Start with All Real Numbers and rule things out. In this case, nothing is ruled out.

Range - What can you get out? Start with All Real Numbers and rule things out. In this case, that absolute value is NEVER negative. The very least you can get from that absolute value is zero (0). This makes the minimum value of the entire expression -3. We just ruled out everything less than -3.