# Math Help - this is so confusing...

1. ## this is so confusing...

i have to solve for y for these 3 problems...where do i start?

yx^2 + yz^3 = t

x/r + 2/3(yz) = 4y

y(3^2) + 1 = 2^4 - y(1^3)

2. Originally Posted by IgnoranceIsBliss
i have to solve for y for these 3 problems...where do i start?

yx^2 + yz^3 = t We see here that the first two terms have a common factor of y: $y(x^2+z^3)=t$. You can take it from here...I'm sure you can.

x/r + 2/3(yz) = 4y Do a little manipulation: $\frac{x}{r}=4y-\tfrac{2}{3}(yz)$. The two terms on the right side of the equation have a common factor of y, so we see that $\frac{x}{r}=\left(4-\tfrac{2}{3}z\right)y$. I'm sure you can take it from here.

y(3^2) + 1 = 2^4 - y(1^3) Simply and then group common terms togther: $9y+1=16-y\implies 10y=15$. I'm sure you can take it from here.
Does this make sense?

--Chris

3. yeah it makes sense...thanks!