Originally Posted by
IgnoranceIsBliss i have to solve for y for these 3 problems...where do i start?
yx^2 + yz^3 = t We see here that the first two terms have a common factor of y: $\displaystyle y(x^2+z^3)=t$. You can take it from here...I'm sure you can.
x/r + 2/3(yz) = 4y Do a little manipulation: $\displaystyle \frac{x}{r}=4y-\tfrac{2}{3}(yz)$. The two terms on the right side of the equation have a common factor of y, so we see that $\displaystyle \frac{x}{r}=\left(4-\tfrac{2}{3}z\right)y$. I'm sure you can take it from here.
y(3^2) + 1 = 2^4 - y(1^3) Simply and then group common terms togther: $\displaystyle 9y+1=16-y\implies 10y=15$. I'm sure you can take it from here.