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Math Help - this is so confusing...

  1. #1
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    this is so confusing...

    i have to solve for y for these 3 problems...where do i start?

    yx^2 + yz^3 = t


    x/r + 2/3(yz) = 4y


    y(3^2) + 1 = 2^4 - y(1^3)
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by IgnoranceIsBliss View Post
    i have to solve for y for these 3 problems...where do i start?

    yx^2 + yz^3 = t We see here that the first two terms have a common factor of y: y(x^2+z^3)=t. You can take it from here...I'm sure you can.


    x/r + 2/3(yz) = 4y Do a little manipulation: \frac{x}{r}=4y-\tfrac{2}{3}(yz). The two terms on the right side of the equation have a common factor of y, so we see that \frac{x}{r}=\left(4-\tfrac{2}{3}z\right)y. I'm sure you can take it from here.


    y(3^2) + 1 = 2^4 - y(1^3) Simply and then group common terms togther: 9y+1=16-y\implies 10y=15. I'm sure you can take it from here.
    Does this make sense?

    --Chris
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  3. #3
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    yeah it makes sense...thanks!
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