What would be the result of the following divisions?

a. 1/0

b. 1/INFINITY

c. INFINITY/0

d. 0/INFINITY

e. INFINITY/1

f. INFINITY/INFINITY

g. 0/0

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- August 6th 2008, 05:29 PManirbanDivision Result
What would be the result of the following divisions?

a. 1/0

b. 1/INFINITY

c. INFINITY/0

d. 0/INFINITY

e. INFINITY/1

f. INFINITY/INFINITY

g. 0/0 - August 6th 2008, 05:39 PMDubulus
depending on what course you are taking, you can use limits to solve most of these, but if not, you simply say they do not exist.

a. 1/0 Divide by 0, does not exist

b. 1/INFINITY does not exist

c. INFINITY/0 divide by 0, does not exist

d. 0/INFINITY = 0 (0 divided by anything is 0)

e. INFINITY/1 = INFINITY (dividing in 1 piece is just itself)

f. INFINITY/INFINITY = 1 (x/x is always 1)

g. 0/0 = divide by 0, does not exist - August 6th 2008, 05:42 PMSerena's Girl
a.) 1/0 = infinity (any positive real number divided by zero is infinity)

b.) 1/infinity = 0 (any real number divided by infinity is zero)

c.) infinity/0 = infinity

say, infinity = r/0, where r = a positive real number

so... (r/0) / 0 = r / (0*0) = infinity

d.) 0/infinity = 0

0 / (r/0) = (0 * 0)/r = 0

e.) infinity/1 = infinity

(Divide infinity by any positive number and you obtain infinity. Divide infinity by any negative number and you obtain negative infinity.)

f.) infinity/infinity = indeterminate

say, infinity in the numerator = r/0. denominator = s/0, wherein s = a positive real number

so... (r / 0) / (s / 0) = r/s

But what is r/s? It can be any rational number. So the answer is indeterminate.

g.) 0/0 = indeterminate

say, numerator = r*0, denominator = s*0

so... (r*0) / (s*0) = r/s

Again, r/s can be any rational number. Hence, indeterminate. - August 8th 2008, 04:38 AMCoffee Cat
I saw this site (Math Forum - Ask Dr. Math) just now, and it has an interesting bunch of operations involving infinity and zero. (Sleepy)

- August 8th 2008, 08:41 AManirban
Wao thanks for the link friend! :)