ok, this is the task:
8/ x²-4 + 6/ 3x -6 =
i know the first step, which is:
8*(3x-6) + 6*(x²-4) / (x²-4)*(3x-6)
but then, i dont know what to do
$\displaystyle \frac{8}{x^2-4} + \frac{6}{3x-6}$
$\displaystyle =\frac{(8)(3x-6) + (6)(x^2 - 4)}{(x^2-4)(3x-6)}$
$\displaystyle =\frac{6x^2 +24x -72}{(x^2-4)(3x-6)}$
$\displaystyle =\frac{(6)(x^2 + 4x - 12)}{(3)(x+2)(x-2)(x-2)}$
$\displaystyle =\frac{(6)(x-2)(x+6)}{(x+2)(3)(x-2)^2}$
Can you simplify and finish the question off now?