how can i solve this

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Aug 6th 2008, 08:45 AM
makaveli89

how can i solve this

ok, this is the task:

8/ x²-4 + 6/ 3x -6 =

i know the first step, which is:

8*(3x-6) + 6*(x²-4) / (x²-4)*(3x-6)

but then, i dont know what to do
Aug 6th 2008, 09:10 AM
nikhil

Quote:

Originally Posted by makaveli89

ok, this is the task:

8/ x²-4 + 6/ 3x -6 =

i know the first step, which is:

8*(3x-6) + 6*(x²-4) / (x²-4)*(3x-6)

but then, i dont know what to do

8/ x²-4 + 6/ 3x -6 =???
Well mathematically your first step is right!
Aug 6th 2008, 09:11 AM
Simplicity

Quote:

Originally Posted by makaveli89

ok, this is the task:

8/ x²-4 + 6/ 3x -6 =

i know the first step, which is:

8*(3x-6) + 6*(x²-4) / (x²-4)*(3x-6)

but then, i dont know what to do

$\frac{8}{x^2-4} + \frac{6}{3x-6}$

$=\frac{(8)(3x-6) + (6)(x^2 - 4)}{(x^2-4)(3x-6)}$

$=\frac{6x^2 +24x -72}{(x^2-4)(3x-6)}$

$=\frac{(6)(x^2 + 4x - 12)}{(3)(x+2)(x-2)(x-2)}$

$=\frac{(6)(x-2)(x+6)}{(x+2)(3)(x-2)^2}$

Can you simplify and finish the question off now? :)

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