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Math Help - Division in binary (repeated subtraction method)

  1. #1
    Newbie scott_237's Avatar
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    Division in binary (repeated subtraction method)

    Divide 1000000001 (base 2) by 10011 (base 2)

    answer = 11011 using repeated subtraction but I have no idea what is going on, here is a link to the pdf exam paper and look at the answer to question 1) (b) iii) LINK - can somebody please explain what is going on here???
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  2. #2
    MHF Contributor
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    First Round is easy

    0111111111
    0000010011

    Just subtract bit-wise

    0111101100 - That's 01

    It's the second round where it gets interesting.

    0111101100
    0000010011

    The problem starts right off. You must borrow from two digits left, giving

    011110101(10)
    0000010011

    There's another problem later on. Borrow again.

    01110(10)0101(10)
    0000010011

    Now we're ready to subtract.

    0111011001 - That's 10

    It's tedious, but it's not tricky for any other reason.
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