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Math Help - how do i solve this?

  1. #1
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    how do i solve this?

    6In x = -4
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  2. #2
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    Why are some users here using “In” in place of ln or Ln for the functional notation for the natural logarithms?
     \begin{array}{l}<br />
 6\ln (x) =  - 4 \\ <br />
 \ln \left( {x^6 } \right) =  - 4 \\ <br />
 x^6  = e^{ - 4}  \\ <br />
 x = e^{ - \frac{2}{3}}  \\ <br />
 \end{array}
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  3. #3
    Junior Member
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    6lnx=-4
    lnx= -4/6
    lnx= -2/3
    by the definition of logarithm

    x= e^-2/3
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