# Math Help - how do i solve this?

1. ## how do i solve this?

6In x = -4

2. Why are some users here using “In” in place of ln or Ln for the functional notation for the natural logarithms?
$\begin{array}{l}
6\ln (x) = - 4 \\
\ln \left( {x^6 } \right) = - 4 \\
x^6 = e^{ - 4} \\
x = e^{ - \frac{2}{3}} \\
\end{array}$

3. 6lnx=-4
lnx= -4/6
lnx= -2/3
by the definition of logarithm

x= e^-2/3