how do i solve this?

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August 2nd 2008, 02:43 PM
brumby_3

how do i solve this?

6In x = -4
August 2nd 2008, 02:52 PM
Plato

Why are some users here using “In” in place of ln or Ln for the functional notation for the natural logarithms?
$\begin{array}{l} 6\ln (x) = - 4 \\ \ln \left( {x^6 } \right) = - 4 \\ x^6 = e^{ - 4} \\ x = e^{ - \frac{2}{3}} \\ \end{array}$
August 2nd 2008, 02:58 PM
tutor

6lnx=-4
lnx= -4/6
lnx= -2/3
by the definition of logarithm

x= e^-2/3

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