x.y=?

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Originally Posted by OPETH x.y=?

Hello, Originally Posted by OPETH x.y=? This can also be solved without using logarithms : From (2) we get that which gives, when substituting in (1) : hence

Originally Posted by masters I obviously misread the exercise, but I'll finish up the mess that I started to hopefully arrive at the same conclusion as flyingsquirrel.

Hello, OPETH! Your answer is correct, masters! Here's a slight variation of flyingsquirrel's solution . . . Given: . . . . . . . We have: . . . . . . . . . Equate [1] and [2]: . Therefore: .