3e^[4x + 2] = 9

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- Aug 1st 2008, 09:40 PMbrumby_3please help me solve this
3e^[4x + 2] = 9

- Aug 1st 2008, 09:43 PM11rdc11
I think the answer is x= {(ln3)-2}/4

- Aug 1st 2008, 09:50 PMtutor
Hi friend

given

3e^(4x+2)=9

e^(4x+2)=3

by using the definition of logarithm

we get as

log3 to the base e=4x+2

x=(log3-2)/4

(Nod)(Clapping)