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Math Help - extracting roots

  1. #1
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    extracting roots

    I don't know how to simplify these tasks:

    1. √2 + √32 =

    2. 3*
    √44 + 7*√99 =
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  2. #2
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    Quote Originally Posted by makaveli89 View Post
    I don't know how to simplify these tasks:

    1. √2 + √32 =

    2. 3*
    √44 + 7*√99 =
    I'll do the first one, and then can you finish the second one?

    \sqrt{2} + \sqrt{32}

    You can turn that into:

    \sqrt{2} + \sqrt{16\cdot 2}

    which can be broken up into:

    \sqrt{2} + \sqrt{16}\sqrt{2}

    Now the square root of 16 is 4 so we now have:

    \sqrt{2} + 4\sqrt{2}

    So then we just add them

    5\sqrt{2}

    so: \sqrt{2} + \sqrt{32} = 5\sqrt{2}

    You do almost the same thing for the other one, so you should try it out yourself.
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  3. #3
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    3*√44 + 7*√99 =

    3*
    √11 * √4 + 7* √11 * √9

    = 3*2
    √11 + 7*3 √11

    = 27 *
    √11
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  4. #4
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    Quote Originally Posted by makaveli89 View Post
    3*√44 + 7*√99 =

    3*
    √11 * √4 + 7* √11 * √9

    = 3*2
    √11 + 7*3 √11

    = 27 *
    √11
    Yep that's exactly right.
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  5. #5
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    Colaba mumbai india
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    Exclamation Complex but easy

    1. √2 + √32
    √2 + (√2 * √2 * √2 * √2 * √2)
    √2 + 4√2
    5√2

    2. 3 = √3 * √3
    7 = √7 * √7
    Therefore-
    √396 + √4851 = 27 * √11
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  6. #6
    Grand Panjandrum
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    Quote Originally Posted by carl_patel View Post
    2. 3 = √3 * √3
    7 = √7 * √7
    Therefore-
    √396 + √4851 = 27 * √11
    The gap in this is too large. A solution if it is complete should comprise a number of steps each obviously following from its predecessors, or with an explanation in words of why it does.

    Also we try to discourage people from giving complete answers to questions, or answers to all the parts of a question, hints, and/or partial answers are preferred.

    RonL
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