x^2-x-6/x^2-4=

2. Originally Posted by mljerez
x^2-x-6/x^2-4=
start by factorizing both the denominator and numerator, note that the bottom is the difference of two squares (you remember how to do that, right?)

$\frac {x^2 - x - 6}{x^2 - 4} = \frac {(x + 2)(x - 3)}{(x + 2)(x - 2)}$

now what?

3. $\frac{x^2-x-6}{x^2-4}=\frac{(x-3)(x+2)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

4. x^2-x-6/x^2-4
=(x-3)(x+2)/(x-2)(x+2)
(x-3)/(x-2)