Could you please help with this?

**mljerez** · July 31st 2008, 11:47 AM

x^2-x-6/x^2-4=

**Jhevon** · July 31st 2008, 12:05 PM

Originally Posted by mljerez

x^2-x-6/x^2-4=

start by factorizing both the denominator and numerator, note that the bottom is the difference of two squares (you remember how to do that, right?)

$\frac {x^2 - x - 6}{x^2 - 4} = \frac {(x + 2)(x - 3)}{(x + 2)(x - 2)}$

now what?

**red_dog** · July 31st 2008, 12:07 PM

$\frac{x^2-x-6}{x^2-4}=\frac{(x-3)(x+2)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

**tutor** · July 31st 2008, 04:36 PM

x^2-x-6/x^2-4
=(x-3)(x+2)/(x-2)(x+2)
(x-3)/(x-2)

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Could you please help with this?