x^2-x-6/x^2-4=

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Originally Posted by mljerez x^2-x-6/x^2-4= start by factorizing both the denominator and numerator, note that the bottom is the difference of two squares (you remember how to do that, right?) $\displaystyle \frac {x^2 - x - 6}{x^2 - 4} = \frac {(x + 2)(x - 3)}{(x + 2)(x - 2)}$ now what?

$\displaystyle \frac{x^2-x-6}{x^2-4}=\frac{(x-3)(x+2)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

x^2-x-6/x^2-4 =(x-3)(x+2)/(x-2)(x+2) (x-3)/(x-2)