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Math Help - Could you please help with this?

  1. #1
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    Could you please help with this?

    x^2-x-6/x^2-4=
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mljerez View Post
    x^2-x-6/x^2-4=
    start by factorizing both the denominator and numerator, note that the bottom is the difference of two squares (you remember how to do that, right?)

    \frac {x^2 - x - 6}{x^2 - 4} = \frac {(x + 2)(x - 3)}{(x + 2)(x - 2)}

    now what?
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  3. #3
    MHF Contributor red_dog's Avatar
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    \frac{x^2-x-6}{x^2-4}=\frac{(x-3)(x+2)}{(x-2)(x+2)}=\frac{x-3}{x-2}
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  4. #4
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    Cool

    x^2-x-6/x^2-4
    =(x-3)(x+2)/(x-2)(x+2)
    (x-3)/(x-2)
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