solve each forumla for the specified variable.

d = cube root 16Mr^2 divide by m

2. Hi
Originally Posted by comet2000
solve each forumla for the specified variable.

d = cube root 16Mr^2 divide by m
Is it $\displaystyle d=\sqrt[3]{\frac{16Mr^2}{m}}$ ? (if not, please, write the formula using parenthesis)

What is the "specified variable" ?

3. Originally Posted by flyingsquirrel
Hi

Is it $\displaystyle d=\sqrt[3]{\frac{16Mr^2}{m}}$ ? (if not, please, write the formula using parenthesis)

What is the "specified variable" ?
yes, that is it.
opps, sorry.
$\displaystyle d=\sqrt[3]{\frac{16Mr^2}{m}}$ for M

4. Originally Posted by comet2000
yes, that is it.
opps, sorry.
$\displaystyle d=\sqrt[3]{\frac{16Mr^2}{m}}$ for M
OK then recall that $\displaystyle y=\sqrt[3]{x} \Longleftrightarrow y^3=\sqrt[3]{x}^3=x$. Using this, we get
$\displaystyle d=\sqrt[3]{\frac{16Mr^2}{m}} \Longleftrightarrow d^3=\frac{16Mr^2}{m}$
and you're able to solve the last equation for $\displaystyle M$, aren't you ?