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Math Help - radicals

  1. #1
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    radicals

    solve each forumla for the specified variable.

    d = cube root 16Mr^2 divide by m
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  2. #2
    Super Member flyingsquirrel's Avatar
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    Hi
    Quote Originally Posted by comet2000 View Post
    solve each forumla for the specified variable.

    d = cube root 16Mr^2 divide by m
    Is it d=\sqrt[3]{\frac{16Mr^2}{m}} ? (if not, please, write the formula using parenthesis)

    What is the "specified variable" ?
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  3. #3
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    Quote Originally Posted by flyingsquirrel View Post
    Hi


    Is it d=\sqrt[3]{\frac{16Mr^2}{m}} ? (if not, please, write the formula using parenthesis)

    What is the "specified variable" ?
    yes, that is it.
    opps, sorry.
    d=\sqrt[3]{\frac{16Mr^2}{m}} for M
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  4. #4
    Super Member flyingsquirrel's Avatar
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    Quote Originally Posted by comet2000 View Post
    yes, that is it.
    opps, sorry.
    d=\sqrt[3]{\frac{16Mr^2}{m}} for M
    OK then recall that y=\sqrt[3]{x} \Longleftrightarrow y^3=\sqrt[3]{x}^3=x. Using this, we get
    d=\sqrt[3]{\frac{16Mr^2}{m}} \Longleftrightarrow d^3=\frac{16Mr^2}{m}
    and you're able to solve the last equation for M, aren't you ?
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