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Math Help - Desperately need help with random complex number problem

  1. #1
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    Question Desperately need help with random complex number problem

    s=R/w^4L^2C^2+j(2/wc-1/w^3LC^2)

    if the imaginary term equates to 0, show that the equation can be written as R=S/4
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  2. #2
    Super Member flyingsquirrel's Avatar
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    Hello

    Quote Originally Posted by jonlynn3936 View Post
    s=R/w^4L^2C^2+j(2/wc-1/w^3LC^2)

    if the imaginary term equates to 0, show that the equation can be written as R=S/4
    We have <br />
S=\frac{R}{\omega^4L^2C^2}+\jmath\left( \frac{2}{\omega C}-\frac{1}{\omega^3 LC^2}\right) and we know that the imaginary part of S equals 0. It gives an equation : \frac{2}{\omega C}-\frac{1}{\omega^3 LC^2}=0 from which you can get the value of \omega. (hint : factor by \frac{1}{\omega C} to solve this equation) Once you've found \omega you're done since S=\frac{R}{\omega^4L^2C^2}=\ldots
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  3. #3
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    Thanks, but am still a bit confused. Do you treat the sum =0 as you would a normal fraction or do something else to it? Having a brain blip!!!
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  4. #4
    Super Member flyingsquirrel's Avatar
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    Quote Originally Posted by jonlynn3936 View Post
    Thanks, but am still a bit confused. Do you treat the sum =0 as you would a normal fraction or do something else to it? Having a brain blip!!!
    You can treat it as a normal sum of fractions : bring the two fractions to the same denominator and then solve \text{numerator}=0. You can also follow the hint I've given : factoring by \frac{1}{\omega C} should give you two equations (one of which has no solutions) which can be solved for \omega.
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  5. #5
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    thanks

    Cheers for your help, was REALLY obvious and couldn't see the solution for looking at it. TOP MAN!!!
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