Hi, im having problems with a simple equation that looks like this:

$\displaystyle \sqrt{x+3} = \sqrt{x-2} + \sqrt{x-5}$

After squaring both sides i have: $\displaystyle x+3=2x-7 +2\sqrt{x-2}\cdot \sqrt{x-5} \rightarrow x-10+2 \cdot (x-2)^\frac{1}{2} \cdot (x-5) ^\frac {1}{2} $ Wich gives: $\displaystyle x-10+2x^{2}-14x+20=0$

However, the anser should be 6 and i get 4. Im not sure about what i am doing wrong =/