1. restrictions for x

4x+7
9x-5

2. We know that zero cannot be in the denominator since dividing by zero is never allowed. Therefore, let's set the denominator in your problem equal to zero and solve for x. Your answer will the only restriction on x.

-Andy

3. Originally Posted by LolaRN
4x+7
9x-5
The denominator cannot be equal to zero.