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Math Help - restrictions for x

  1. #1
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    restrictions for x

    4x+7
    9x-5
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  2. #2
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    We know that zero cannot be in the denominator since dividing by zero is never allowed. Therefore, let's set the denominator in your problem equal to zero and solve for x. Your answer will the only restriction on x.

    -Andy
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by LolaRN View Post
    4x+7
    9x-5
    The denominator cannot be equal to zero.

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