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Math Help - need help with radicals

  1. #1
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    need help with radicals

    how can i solve this? help please

    1)1/4 x√3y - 3/2 x√3y

    2) √50x^2y^5 - 13y√2x^2y^3 + xy√98y^3
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  2. #2
    Super Member
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    I'm going to assume that they're asking you to simplify:
    1.
    a. Given: 1/4 x√3y - 3/2 x√3y
    b. Combine fractions: (x√3y)/4 - (6x√3y)/4 = (-5x√3y/4)

    2.
    a. Given: √50x^2y^5 - 13y√2x^2y^3 + xy√98y^3
    b. Factor: √(2*5^2*x^2*y^4*y) - 13y√(2*x^2*y^2*y) + xy√(2*7^2*y^2*y)
    c. Take 'em out: 5xy^2√2y - 13xy^2√2y + 7xy^2√2y
    d. Combine: -xy^2√2y
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  3. #3
    Super Member

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    Lexington, MA (USA)
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    Hello, DDuNsT!

    Here's my approach to #2 . . .



    . . . . . . . . . . . .________ . - - . ._______ . . . .____
    Simplify: .(2) . √50xy^5 - 13y√2xy + xy√98y

    . - - . . . . . . .________ . . . . . ___________ . . . . . _____________
    First term: . √50xy^5 . = . √252xy^4y . = . √(25xy^4)(2y)
    . . . . . ._________ . .__ . . - - . . . .__
    . . = . √25xy^4 √2y . = . 5xy√2y

    . . . . . . . . . . . . . . .______ . . . . . . . .________ . . . . . . . .________
    Second term: . -13y√2xy . = . -13y√2xyy . = . -13y√(xy)(2y)
    . . . . . . . . . . .__ . . - - . . . . . __
    . . = . -13yxy√2y . = . -13xy√2y

    . - - . . . . . . . . ____ . . . . . . ________ . - - . . ._________
    Last term: . xy√98y . = . xy√492yy . = . xy√(49y)(2y)
    . - - . . . . . . __ . - . . . . . .__
    . . = . xy7y√2y . = . 7xy√2y


    Now combine the three terms . . .

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