# not sure what kind of problem

• Jul 26th 2008, 09:58 PM
blackdove
not sure what kind of problem
givens:
(a/x) = (b/k)
(a/2b) = d(3x/k)

problem;
Find the vaule of "d"
• Jul 27th 2008, 12:15 AM
ticbol
Quote:

Originally Posted by mr fantastic
..

May butt in, Mr F.
The poster, blackdove, titled his post "not sure what kind of problem".

I played around with his post and I got a numerical result. May I post it?

givens:
(a/x) = (b/k)
(a/2b) = d(3x/k)

problem;
Find the vaule of "d"

From (a/x) = (b/k),
cross multiply,
bx = ak

From the (a /2b) = d(3x /k),
a/ 2b = 3dx /k
Cross multiply,
2b(3dx) = ak
6bdx = ak

ak = ak,
bx = 6bdx
1 = 6d
d = 1/6 --------answer.
• Jul 27th 2008, 01:18 AM
mr fantastic
Quote:

Originally Posted by ticbol
May butt in, Mr F.
The poster, blackdove, titled his post "not sure what kind of problem".

I played around with his post and I got a numerical result. May I post it?

givens:
(a/x) = (b/k)
(a/2b) = d(3x/k)

problem;
Find the vaule of "d"

From (a/x) = (b/k),
cross multiply,
bx = ak

From the (a /2b) = d(3x /k),
a/ 2b = 3dx /k
Cross multiply,
2b(3dx) = ak
6bdx = ak

ak = ak,
bx = 6bdx
1 = 6d
d = 1/6 --------answer.

Quite right. I should have given it a closer look. In fact, some simple re-arranging gives:

(1) => a/b = x/k

(2) => a/b = (6d) x/k

So clearly 6d = 1 etc.