Results 1 to 5 of 5

Math Help - I need complete solution fast.

  1. #1
    Junior Member
    Joined
    Jul 2008
    Posts
    47

    I need complete solution fast.

    -2 4 -6 2
    Let A= and B= find each of the following.
    0 3 4 0



    -2A+4B
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by norwoodjay View Post
    -2 4 -6 2
    Let A= and B= find each of the following.
    0 3 4 0



    -2A+4B
    I assume A is the matrix [-2 4 -6 2] and B is the matrix [0 3 4 0] ...
    is this correct?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by norwoodjay View Post
    -2 4 -6 2
    Let A= and B= find each of the following.
    0 3 4 0



    -2A+4B
    Is this what you are asking:

    A = [-2 4 -6 2}
    B = [0 3 4 0]

    -2A + 4B = [4 -8 12 -4] + [0 12 16 0] = [4 4 28 -4]
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member
    Joined
    Jul 2008
    Posts
    47
    A is -2 4 and B is -6 2 both A snd B have Brackets around them.
    0 3 4 3
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Hello,

    Code:
      -2  4
    A=
       0  3
    Code:
      -6  2
    B=
       4  0
    -2A means that you multiply each element of A by -2
    4B means that you multiply them by 4.

    Addition will be adding the elements that are at the same place. For example, A+B will give
    Code:
    -2-6   4+2
    0+4   3+0
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. I need help complete solution
    Posted in the Algebra Forum
    Replies: 2
    Last Post: July 24th 2008, 10:51 AM
  2. complete solution using Cramer's rule
    Posted in the Algebra Forum
    Replies: 1
    Last Post: July 24th 2008, 10:04 AM
  3. I need complete solution
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: July 15th 2008, 10:26 AM
  4. complete the inequality give the solution set
    Posted in the Algebra Forum
    Replies: 1
    Last Post: December 11th 2007, 06:03 AM
  5. need a urgent and complete solution for this
    Posted in the Geometry Forum
    Replies: 1
    Last Post: September 1st 2007, 11:05 PM

Search Tags


/mathhelpforum @mathhelpforum