"The length of the rectangle is ½ plus 50 sq. ft. of the width."
How can a length be measured in square feet?
Create an example of your own of a real-life word problem which can be solved using algebraic equations. Write the problem, then solve the problem. Show the algebraic equations that are involved including all necessary steps taken to get the answer.
This involves a rectangle. The perimeter of the rectangle is 700 square feet. The length of the rectangle is ½ plus 50 sq. ft. of the width. What is the width and length? Let Y be the Length and X be the width.