Hello,

Your mistake is here :

If you take 4A from both sides, it's :then take 4A from both sides to get -2A/3=8

8=(2A/3)-4A

But to substract two elements, they gotta have the same denominator. So write 4A=12A/3 and then do the substraction.

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- Jul 24th 2008, 04:33 AM #1

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## need help

2A/3=8+4A

my problem is to figure out what A is alone but my answer doesnt match the book, i know its either A=12/5 or A=-2.4 but my answer doesnt come close.

first i tried it 2A/3=8+4A then take 4A from both sides to get -2A/3=8, times by 3 to get rid of it. -2A=24, then devide by -2, A= -12.

- Jul 24th 2008, 04:37 AM #2

- Jul 24th 2008, 04:52 AM #3

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sorry i dont understand exactly why you increased the 2A to 12A, am i suppose to look at 2A/3 as a fraction?

It would be a really big help if you could explain alittle step by step, i havent done this type of math for a awhile and trying to get a jump on it again so.. kind tell me in the most simple way please

- Jul 24th 2008, 05:03 AM #4
I'll try

2A/3=8+4A.

--------------------

What you did :

(2A/3)-4A=-2A/3

Remember the rules of operations (pemdos or bodmas), the division comes before the substraction !

What you did here is first substract 4A to 2A and then divide by 3. This is false.

2A/3 - 4A = 8

Multiply both sides by 3 in order to get rid of the division.

--> 2A - 12A=24

and now you can solve

- Jul 24th 2008, 05:26 AM #5

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