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Math Help - 3 quick review problems

  1. #1
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    3 quick review problems

    Solve for y

    y=p^2(c) p=100 c=1/100




    x=y/z^2 x=4 z=5



    y=pc p=100 c=1/100
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  2. #2
    MHF Contributor
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    Quote Originally Posted by ITTTechstudent View Post
    Solve for y

    y=p^2(c) p=100 c=1/100
    You must learn the concept of substitution.

    y = (100)^2(1/100)

    The values for p and c have been substituted into the equation. You need a little algebra to simplify.

    Let's see what you get, then tackle the other two.
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