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Math Help - partial function

  1. #1
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    partial function

    express(x-2)/[(x^2+1)(x-1)^2] in partial fractions in its simplest form.

    express 7x+4/[(x-3)(x+2)^2] as the sum of partial fraction with constant numerators
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by qweiop90 View Post
    express(x-2)/[(x^2+1)(x-1)^2] in partial fractions in its simplest form.

    express 7x+4/[(x-3)(x+2)^2] as the sum of partial fraction with constant numerators
    \frac{x-2}{(x^2+1)(x-1)^2}=\frac{Ax+B}{x^2+1}+\frac{C}{x-1}+\frac{D}{(x-1)^2}

    Can you take it from here?

    \frac{7x+4}{(x-3)(x+2)^2}=\frac{A}{x-3}+\frac{B}{x+2}+\frac{C}{(x+2)^2}

    Can you take it from here?

    --Chris
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  3. #3
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    i try thanks for your help
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  4. #4
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    i couldnt do question 1. i stuck at the half. can you please provide me the solution?
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  5. #5
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    Talking

    hi

    Here i am showing the answer of the first problem, the the other guy he showed to how to frame the problem that's fantastic way , i will do the remaining steps to show the answers here

    7x+4=A(x+2)^2+B(x+2)(x-3)+c(x-3)

    plug x=3 in the above equation u will get
    25A=25

    then A=1

    plug x=-2, then C=2

    finally equating the coefficient of x^2 on both sides we get it as
    A+B=0
    B=-1


    =1/(x-3)-1/(x+2)+2/(x+2)^2 is the final answer
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