1. ## partial function

express(x-2)/[(x^2+1)(x-1)^2] in partial fractions in its simplest form.

express 7x+4/[(x-3)(x+2)^2] as the sum of partial fraction with constant numerators

2. Originally Posted by qweiop90
express(x-2)/[(x^2+1)(x-1)^2] in partial fractions in its simplest form.

express 7x+4/[(x-3)(x+2)^2] as the sum of partial fraction with constant numerators
$\frac{x-2}{(x^2+1)(x-1)^2}=\frac{Ax+B}{x^2+1}+\frac{C}{x-1}+\frac{D}{(x-1)^2}$

Can you take it from here?

$\frac{7x+4}{(x-3)(x+2)^2}=\frac{A}{x-3}+\frac{B}{x+2}+\frac{C}{(x+2)^2}$

Can you take it from here?

--Chris

3. i try thanks for your help

4. i couldnt do question 1. i stuck at the half. can you please provide me the solution?

5. hi

Here i am showing the answer of the first problem, the the other guy he showed to how to frame the problem that's fantastic way , i will do the remaining steps to show the answers here

7x+4=A(x+2)^2+B(x+2)(x-3)+c(x-3)

plug x=3 in the above equation u will get
25A=25

then A=1

plug x=-2, then C=2

finally equating the coefficient of x^2 on both sides we get it as
A+B=0
B=-1