Is this right? I'm dividing complex fractions....
8x^2 divided by 4x
over
x^2 -25 divided by 3x+15
I flipped the other fraction and changed the problem to multiplication
8x^2 ovwer x^2 -25 divided by 3x +15 divided by 4x
I factored x^2 -25 and got x+5 and x-5 and divided 8 by 4 and got two and 4 divided by 4 is 1 or x
and now I have 2 times 3x plus 15 over x...is that correct?
You are getting confused with constant and variables (Originally Posted by Laura901
). They cannot cancel each other out. Constants can only cancel out constants and variables can only cancel variables. Let me explain the procedure:
You correctly said to flip a fraction and multiply, hence:
Simplify the expressions.can be simplied to
as the denominator has
and rules of indices says
so we have
(Notice, we only let constants work with constant
and variables work with variable
). For
, the numerator and the denominator can be factorised to get
. We have
on the numerator and the denominator so we can cancel it out to get
So we get:
For fractions, when we have to multiply, we multiply the numerator (top) together and we multiply the denominator (bottom) togather. So we get:
} = \frac{(3)(2x)}{(1)(x+5)} = \frac{6x}{x+5})
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