1. ## evaluating logarithmic expressions

dang logs!

2. $log_3(27^\frac {1}{9})$
$\frac {1}{9}log_3(27)$
$\frac {1}{9}log_3(3^3)$
$\frac {1}{9}3log_3(3)$
$\frac {1}{3}$

3. Originally Posted by mankvill
dang logs!
You only have to change $\sqrt[9]{27}$ into an expression with the base 3. The exponent of this expression is the logarithm you are looking for:

$\sqrt[9]{27} = \left(3^{3}\right)^{\frac19}$

I'm a bit curious: I know decimal logarithms and natural logarithms but I have never heard about dang logarithms

4. Therfore the answer will be