Polynomial division and exponent in fraction

**MistaMista** · July 20th 2008, 11:10 AM

if i have x^3 over 3 and i substitute in 1 what do i get does is the whole fraction cubed.

Also how do i polynomially divide 3x^3+ 11/4 x^2 - 1/2 x - 1/4 divided by x+1
I just need to get the quadratic equation i cant get the last number it might be an algebra mistake but i cant find it.

For clarification above 11/4 x^2 is eleven fourths x squared.

**Soroban** · July 20th 2008, 01:21 PM

Hello, MistaMista!

If I have $\frac{x^3}{3}$ and i substitute in $x = 1$
what do i get? .Is the whole fraction cubed? . . . . no

What do we have?

We have: . $\frac{(1)^3}{3} \;=\;\frac{1}{3}$

How do I divide: . $\left(3x^3+ \frac{11}{4}x^2 - \frac{1}{2}x - \frac{1}{4}\right) \;\div\; (x+1)$ . . . . Very carefully!

$\begin{array}{cccccc}& & & 3x^2 & -\frac{1}{4}x & -\frac{1}{4} \\<br /> & & --- & --- & --- & --- \\ x + 1 &^ ) & 3x^3 & +\frac{11}{4}x^2 & -\frac{1}{2}x & -\frac{1}{4} \\ & & 3x^3 & +3x^2 \\ & & --- & --- \\ & & & -\frac{1}{4}x^2 & -\frac{1}{2}x \\ & & & -\frac{1}{4}x^2 & -\frac{1}{4}x^2 \\<br /> & & & --- & --- \\ & & & & -\frac{1}{4}x & -\frac{1}{4} \\ & & & & -\frac{1}{4}x & -\frac{1}{4} \\ & & & & --- & --- \end{array}$

Answer: . $\boxed{3x^2 - \frac{1}{4}x - \frac{1}{4}}$

**MistaMista** · July 20th 2008, 03:03 PM

i see where i was messed up with my subraction of 11/4 minus 3 but thanks

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