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Math Help - lowest common denominator in fraction(help me with this problems)

  1. #1
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    lowest common denominator in fraction(help me with this problems)

    1-(x/x^2-5+4),(x+1/x^2-16)

    2-(6/a6^2-7a+6),(3/a^2-36)

    3-(7/x^2+4x+4),(5/4-x^2)
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  2. #2
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    Quote Originally Posted by manznitaa5 View Post
    1-(x/x^2-5x+4),(x+1/x^2-16) I assume you meant that to be a 5x

    2-(6/a^2-7a+6),(3/a^2-36) I might assume you meant a^2 instead of a6^2

    3-(7/x^2+4x+4),(5/4-x^2)

    1) \frac{x}{x^2-5x+4} \ \  , \ \ \frac{x+1}{x^2-16}

    First, factor the denominators:

    (x-1)(x-4) \ \ , \ \ (x-4)(x+4)

    The LCD is found by using all the different factors the most number of times they appear in any one denominator.

    LCD = (x-1)(x-4)(x+4)

    2) \frac{6}{a^2-7a+6} \ \ , \ \ \frac{3}{a^2-36}

    Same steps as before. Factor the denominators:

    (a-6)(a-1) \ \ , \ \ (a-6)(a+6)

    LCD =

    Can you finish? Try #3 and see how far you get.
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