yes

nice start. now just treat log(x) as a variable and solve for it. what if you have (log3)y = log3 + y. could you solve for y? sure you could. here, of course, y = logxThe second problem:

3^log x = 3x

I attempted but got stuck. Any help will be much appreciated.

3^log x = 3x

log(3^log x) = log 3x

log3logx = log3+logx

we get

so,

can you finish?