the moral of the story: type your problems correctly and use parentheses.
yes, the solutions are which is the same asProblem two states "Find all real and/or imaginary solutions."
3x^2 - 4x + 5 = 0
I use quadratic formula on this problem to get:
4(plus/minus) the square root of (-4)^2 - 4(3)(5)
So, I am left with:
4(plus/minus) the square root of -44 over 6
4(plus/minus) 6.63i over 6
So, my solutions are
10.63i/6 which equals 1.77i
-2.63i/6 which equals -0.44i
I am not sure as to whether or not I worked this one out properly.
or if you prefer: (to two decimal places)
no, is fineMy third and final problem states "Solve the equation by completing the square."
3x^2 - 12x -9 = 0
First off, I divide the problem by 3 to get:
x^2 - 4x - 3 = 0
Then I add three to both sides and square it off to get:
x^2 - 4x + 4 = 7
and I am left with:
(x - 2)^2 = 7
I square everything off and get:
x - 2 = the square root of 7
which then turns into:
x=2(plus/minus) the square root of seven.
I am confident that I worked this one out correctly, but I am unaware as to whether or not I will need to break this one down further or not to get a real solution set.
Any help is more than appreciated. Thank You. )