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Math Help - Simplify (4a^(3/2)) * (2a^1\2))

  1. #1
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    Simplify (4a^(3/2)) * (2a^1\2))

    The question is: Simplify (4a^(3/2)) * (2a^1\2))

    The answer the book gives is: 8a^2

    My work includes:

    1. (4a^(3/2)) * (2a^1\2))
    2. (sqrt(4)^3) * (sqrt(a)^3) * sqrt(2) * sqrt(a)
    3. (sqrt(4)^3) * (sqrt(a)^4 * sqrt(2)
    4. 2^3 * a^2 * sqrt(2)
    Thus: 8a^2 * sqrt(2)

    Is the book wrong, or how do I get rid of that sqrt(2)?

    Thanks
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  2. #2
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    Nevermind, I went about this in completely the wrong way and figured it out.

    (4 * 2) * (a^(3/2)+(1/2)) = 8a^2
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  3. #3
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    Quote Originally Posted by sstecken View Post
    I went about this in completely the wrong way and figured it out.
    Are you SURE you don't want to rethink this sentence?
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  4. #4
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    I went about it in completely the wrong way (first post) and figured it out (second post).

    So to answer your question, no, I don't wish to rethink.
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  5. #5
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    Hi ,

    You can do this answer in simple way by using indices

    (4a^3/2)*(2a1/2)

    =4*2*a^4/2 here we are adding the powers since the bases are same

    =8a^2

    I hope this will find u in simple way
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