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Math Help - just started identities in summer school today in nedd of help.

  1. #1
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    just started identities in summer school today in need of help.

    theta=(T) pie=(P) beta=(B)

    1) simplify: (3(P)/2+(T))
    2)if tan x = 2 find tan((P)/4+x)
    3)if tan(T)= -12/5 and (T) lies in quadrant 2, then what is the value of cos2(T)
    4)if cos(B)= -1/3 and (B)is a second quadrant angle find the tan2(B)
    5)if sin A= -3/5 in quadrant 3, find cos2A



    HERE ARE THE ANSWERS I JUST NEED THE WORK:
    1)-cos(T)
    2)-3
    3)-110/169
    4)4root2/7
    5)7/25
    Last edited by jimC; July 17th 2008 at 01:20 PM.
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  2. #2
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    Quote Originally Posted by jimC View Post
    theta=(T) pie=(P) beta=(B)

    1) simplify: (3(P)/2+(T))
    2)if tan x = 2 find tan((P)/4+x)
    3)if tan(T)= -12/5 and (T) lies in quadrant 2, then what is the value of cos2(T)
    4)if cos(B)= -1/3 and (B)is a second quadrant angle find the tan2(B)
    5)if sin A= -3/5 in quadrant 3, find cos2A



    HERE ARE THE ANSWERS I JUST NEED THE WORK:
    1)-cos(T)
    2)-3
    3)-110/169
    4)4root2/7
    5)7/25
    If you've just started this work it's natural that you'll experience initial difficulty. Having someone do the work for you is not the way to overcome this difficulty.

    It's better that you invest some time and effort in trying to do them yourself. Then post the work you've done and state where you get stuck.

    The help you get will then be much more beneficial.
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  3. #3
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    work ive done

    1) i know im suppose to make it into something like
    sin(T)cos(B)+sin(B)cos(T) and then i think i put in 270degrees for the sines or something like that and then i dont no what to do.


    2) so for this one i think i would have to put it in the form of tan(T)+cos(B)/1-tan(T)tan(B) but for this on to i just couldn't find an example so i need to have it shown to me.


    3,4 and 5)I am quite lost for these ones the only thing i know is to do the pythagerous stuff and get all the sides.
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