1. ## Problems Related with Mensuration.Please solve it.

Plz help for my exams.Only 4 days are left try to solve the whole question please.Plz i need help.I have tried all questions but i am not getting it so plz solve that whole and all questions.

Q1)The length of a rectangle is 4 cm more than its breadth and its perimeter is 11 cm more than its breadth.Find the length and breadth.Find the length and breadth of rectangles.

Q2)The breadth of a floor is 4 meter less than its length.If length and breadth is increased by 1 meter each,then its area increases by 27 square meter.Find the length and breadth of the floor and obtain the area of the floor

Q3)A field is shape of a square.A fence is to be erected around it.The cost of the fence at the rate of Rs 12 per meter will be Rs 2,640.How much paise per square meter?

In Q3 the Rs 12 is INR 12 in INDIA money formet is Rupees paise 1 RS = 100 paise.

2. Originally Posted by prashantvrm
Plz help for my exams.Only 4 days are left try to solve the whole question please.Plz i need help.I have tried all questions but i am not getting it so plz solve that whole and all questions.

Q1)The length of a triangle rectangle is 4 cm more than its breadth and its perimeter is 11 cm more than its breadth.Find the length and breadth.Find the length and breadth of rectangles.
What is a triangle rectangle?

Originally Posted by prashantvrm
Q2)The breadth of a floor is 4 meter less than its length.If length and breadth is increased by 1 meter each,then its area increases by 27 square meter.Find the length and breadth of the floor and obtain the area of the floor
$\displaystyle b = l - 4 \Rightarrow l = b + 4$

$\displaystyle A = lb = (b+4)b = b^2 + 4b$
$\displaystyle A+27 = (l+1)(b+1) = ((b+4) + 1)(b+1) = b^2 + 6b + 5$

sub A value in second equation.

$\displaystyle A+27 = b^2 + 4b + 27 = b^2 + 6b + 5 \Rightarrow 2b = 22 \Rightarrow b = 11, l = b+4 = 15$

3. Originally Posted by Isomorphism
What is a triangle rectangle?

$\displaystyle b = l - 4 \Rightarrow l = b + 4$

$\displaystyle A = lb = (b+4)b = b^2 + 4b$
$\displaystyle A+27 = (l+1)(b+1) = ((b+4) + 1)(b+1) = b^2 + 6b + 5$

sub A value in second equation.

$\displaystyle A+27 = b^2 + 4b + 27 = b^2 + 6b + 5 \Rightarrow 2b = 22 \Rightarrow b = 11, l = b+4 = 15$
Sorry it was written wrong now it is write.

Thanks.

4. Originally Posted by prashantvrm
Q1)The length of a rectangle is 4 cm more than its breadth and its perimeter is 11 cm more than its breadth.Find the length and breadth.Find the length and breadth of rectangles.
$\displaystyle l = b+4 ,\text{ perimeter} = 2(l+b) = 11 + b$
$\displaystyle \Rightarrow 2(b+4 + b) = 11 + b \Rightarrow 2(2b+4) = 4b+8 = 11 + b \Rightarrow 3b = 3 \Rightarrow b=1, l =b+4 = 5$