Not sure where to begin on this one. If you tell me how to do this one, it'd help me with the others.
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Originally Posted by mankvill Not sure where to begin on this one. If you tell me how to do this one, it'd help me with the others. Substitute for y in the second equation to get a quadratic equation. Now solve this quadratic and try both roots to get values for y. Try it
Oh yeah, I always forget to do that! Now I'm having trouble with this! (x-2)(x-2) doesn't work. (x+2)(x-2) doesn't work...
Wait. Is there no solution?
Sigh... x^2+ 4x + 1 = - 3 x^2+ 4x + 4 = 0 (x+2)^2 = 0 x = -2 Substiute this value in y = x^2 + 1 = (-2)^2 + 1 = 4+1 = 5
Originally Posted by Isomorphism Sigh... x^2+ 4x + 1 = - 3 x^2+ 4x + 4 = 0 (x+2)^2 = 0 x = -2 Substiute this value in y = x^2 + 1 = (-2)^2 + 1 = 4+1 = 5 oh, okay. yeah, i'm not good with that. So is there 1 answer: -2,5?
Originally Posted by mankvill oh, okay. yeah, i'm not good with that. So is there 1 answer: -2,5? Yes, after all that working out... you should not be this doubtful
I know, I'm just taking a test right now! Gotta be sure. Thanks!
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