Is 1/3 a solution of z+4/2-z=13/5?
Is 13/4 a solution of x+6/x-2=37/5?
please show me how these problems are done because i have no idea where to start. thank you.
Have you tried substitution?
"Is 1/3 a solution of z+4/2-z=13/5?"
(1/3) + 4/2 - (1/3) = (1/3) + 2 - (1/3) = (1/3) - (1/3) + 2 = 2 Nope!
Now, if you meant $\displaystyle \frac{z+4}{2-z} = \frac{13}{5}$, that would be different, but that is not what you wrote.
Use more parentheses and remember the "Order of Operations". These things matter. Don't ignore them.
If you look at how TKHunny wrote the second part.
$\displaystyle \frac{z+4}{2-z} = \frac{13}{5}$
Multiply both sides by 2-z and 5
(z+4)*5 = (13)*(2-z)
Gives
5z + 20 = 26 -13z
Collect the Z's on one side, so add 13z to both sides and subtract 20 to both sides.
leaves you with 18z = 6
z = 6/18 which can be simplfied into 1/3.
I dont know how to set out the fractions like TKHunny has done though!
If you want to see how the math script is written, all you have to do is quote someone and you will see their LaTeX script in the math /math tags. The command for writing a fraction is \frac{numerator}{denominator}. To put something in math tags, use the math tags button, which appears as a capital letter sigma or summation symbol. Alternatively, you can write the math tags yourself; just don't forget the brackets.
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