Hi I cannot wrap my head around these two problems.
Some help would be greatly appreciated.
and
these questions are a matter of applying log laws
$\displaystyle \log_{a} b = c $
$\displaystyle a^c=b$
so for your case a=2 and c=-3, so sub them into the second equation
the second question is a combination of log laws
$\displaystyle e \log_{a} b = \log_{a} b^e $
and $\displaystyle \log_{a} b + \log_{a} d = \log_{a} (b*d)$
and $\displaystyle \log_{a} b - \log_{a} d = \log_{a} (\frac{b}{d})$
so for the second question rewrite the equation in the form of $\displaystyle \log_{a} b^e $ and then apply the addition and subtraction rules to get your answer
thank you, i think i got it..
$\displaystyle \log_{2} x = -3 $
$\displaystyle 2^{-3}=x$
$\displaystyle x=1/8$
and
$\displaystyle {3/2} \log_{b} 4 - {2/3} \log_{b}8 + \log_{b}2= \log_{b} x $
$\displaystyle \log_{b}4^{3/2}-\log_{b}8^{2/3} + \log_{b}2= \log_{b}x$
$\displaystyle (4^{3/2}) / (8^{2/3})*2=x$
8/2*2
x=4
i hope i am correct..